{"id":18445,"date":"2024-03-03T20:21:44","date_gmt":"2024-03-03T20:21:44","guid":{"rendered":"https:\/\/soicau3088.minhngocxoso.com\/?p=18445"},"modified":"2024-07-09T10:46:58","modified_gmt":"2024-07-09T03:46:58","slug":"lo-xien-la-gi-lo-xien-an-bao-nhieu","status":"publish","type":"post","link":"https:\/\/soicauxsmbmienphi.com\/lo-xien-la-gi-lo-xien-an-bao-nhieu\/","title":{"rendered":"L\u00f4 xi\u00ean l\u00e0 g\u00ec? L\u00f4 xi\u00ean \u0103n bao nhi\u00eau"},"content":{"rendered":"
Trong gi\u1edbi ch\u01a1i l\u00f4 \u0111\u1ec1 hi\u1ec7n nay,ngo\u00e0i vi\u1ec7c soi c\u1ea7u l\u00f4 truy\u1ec1n th\u1ed1ng th\u00ec \u0111\u1ec3 t\u0103ng t\u1ec9 l\u1ec7 \u0103n \u0111\u1eadm m\u00e0 kh\u00f4ng \u00e2m v\u1ed1n nhi\u1ec1u cao th\u1ee7 ch\u1ecdn s\u1eed d\u1ee5ng h\u00ecnh th\u1ee9c soi c\u1ea7u l\u00f4 xi\u00ean. V\u1eady c\u1ee5 th\u1ec3 l\u00f4 xi\u00ean kh\u00e1c l\u00f4 th\u01b0\u1eddng \u1edf ch\u1ed7 n\u00e0o? ch\u01a1i l\u00f4 xi\u00ean l\u00e0 nh\u01b0 th\u1ebf n\u00e0o? C\u00f3 bao nhi\u00eau h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean? T\u1ec9 l\u1ec7 \u0103n l\u00f4 xi\u00ean nh\u01b0 th\u1ebf n\u00e0o? H\u00e3y c\u00f9ng t\u00ecm hi\u1ec3u trong b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y.<\/p>\n
N\u1ebfu ch\u01a1i l\u00f4 th\u01b0\u1eddng l\u00e0 ch\u1ecdn ra m\u1ed9t c\u1eb7p s\u1ed1 nh\u1ea5t \u0111\u1ecbnh, b\u00e1o s\u1ed1 + t\u1ec9 l\u1ec7 c\u01b0\u1ee3c v\u00e0 ch\u1edd k\u1ebft qu\u1ea3. K\u1ebft qu\u1ea3 quay l\u1ed3ng c\u1ea7u XSMB v\u1ec1 \u0111\u00fang s\u1ed1 \u0111\u00f3 th\u00ec b\u1ea1n \u0111\u01b0\u1ee3c \u0103n v\u00e0 v\u1ec1 2, 3 l\u1ea7n th\u00ec c\u1ee9 th\u1ebf g\u1ea5p 2 ho\u1eb7c 3 l\u1ea7n ti\u1ec1n th\u1eafng c\u01b0\u1ee3c.<\/p>\n
Th\u00ec v\u1edbi soi c\u1ea7u l\u00f4 xi\u00ean c\u0169ng kh\u00f4ng c\u00f3 qu\u00e1 nhi\u1ec1u kh\u00e1c bi\u1ec7t. \u0110\u1ec3 ch\u01a1i l\u00f4 xi\u00ean, b\u1ea1n c\u1ea7n soi c\u1ea7u v\u00e0 ch\u1ecdn ra \u00edt nh\u1ea5t 2 c\u1eb7p s\u1ed1 ho\u1eb7c 3, 4 c\u1eb7p s\u1ed1 t\u00f9y theo h\u00ecnh th\u1ee9c (xi\u00ean 2, xi\u00ean 3, xi\u00ean 4) v\u00e0 b\u00e1o c\u00e1c c\u1eb7p s\u1ed1 n\u00e0y c\u00f9ng nhau.<\/p>\n
N\u1ebfu t\u1ed1i \u0111\u00f3 t\u1ea5t c\u1ea3 c\u00e1c c\u1eb7p s\u1ed1 b\u1ea1n ch\u1ecdn b\u00e1o \u0111\u1ec1u xu\u1ea5t hi\u1ec7n trong b\u1ea3ng KQXSMB th\u00ec b\u1ea1n th\u1eafng c\u00f2n n\u1ebfu ch\u1ec9 1 c\u1eb7p b\u1ea1n ch\u1ecdn kh\u00f4ng xu\u1ea5t hi\u1ec7n th\u00ec b\u1ea1n v\u1eabn l\u00e0 ng\u01b0\u1eddi thua cu\u1ed9c.<\/p>\n
B\u1ea1n c\u0169ng bi\u1ebft, k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u00f3 27 gi\u1ea3i nh\u01b0ng th\u01b0\u1eddng ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau v\u00e0 v\u00ec th\u1ebf x\u00e1c su\u1ea5t \u0111\u1ec3 b\u1ea1n c\u00f3 th\u1ec3 n\u1eafm ch\u1eafc c\u01a1 h\u1ed9i \u0103n m\u1ed9t con l\u00f4 truy\u1ec1n th\u1ed1ng ch\u1ec9 kho\u1ea3ng 21,5%. V\u00e0 \u0111\u01b0\u01a1ng nhi\u00ean khi \u0111\u1ed9 kh\u00f3 t\u0103ng d\u1ea7n th\u00ec t\u1ec9 l\u1ec7 win c\u0169ng s\u1ebd theo \u0111\u00f3 m\u00e0 gi\u1ea3m d\u1ea7n (\u0110\u00e2y c\u0169ng ch\u00ednh l\u00e0 l\u00ed do v\u00ec sao soi c\u1ea7u ch\u01a1i l\u00f4 xi\u00ean v\u1ed1n \u00edt m\u00e0 l\u1eddi nhi\u1ec1u).<\/p>\n
Ch\u00fang t\u00f4i \u0111\u00e3 t\u00ednh \u0111\u01b0\u1ee3c x\u00e1c xu\u1ea5t tr\u00fang l\u00f4 xi\u00ean theo t\u1eebng d\u1ea1ng (xi\u00ean 2, xi\u00ean 3 v\u00e0 xi\u00ean 4) c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
\u0110\u1ed1i v\u1edbi xi\u00ean 2, x\u00e1c su\u1ea5t tr\u00fang = 21,5% x 21,5% = 0,0462 \u2013 T\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang ch\u1ec9 c\u00f3 4,6%.<\/p>\n
\u0110\u1ed1i v\u1edbi l\u00f4 xi\u00ean 3, x\u00e1c su\u1ea5t tr\u00fang = 21,5% x 21,5% x 21,5% = 00994 \u2013 T\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi x\u00e1c su\u1ea5t tr\u00fang ch\u1ec9 c\u00f3 0,994%. X\u00e1c xu\u1ea5t n\u00e0y c\u00f2n nh\u1ecf h\u01a1n c\u1ea3 x\u00e1c xu\u1ea5t tr\u00fang \u0111\u1ec1 l\u00e0 1%.<\/p>\n
T\u1eeb c\u00e1c t\u00ednh tr\u00ean ta c\u00f3 th\u1ec3 th\u1ea5y v\u1edbi xi\u00ean 4 th\u00ec x\u00e1c xu\u1ea5t tr\u00fang c\u00f2n nh\u1ecf h\u01a1n r\u1ea5t r\u1ea5t r\u1ea5t nhi\u1ec1u l\u1ea7n. \u1ea4y th\u1ebf nh\u01b0ng \u0111\u00f4i khi v\u1eabn c\u00f3 ng\u01b0\u1eddi tr\u00fang. \u0110i\u1ec1u \u0111\u00f3 ch\u1ee9ng t\u1ecf r\u1eb1ng n\u1ebfu c\u1ee9 ki\u00ean tr\u00ec th\u00ec \u1eaft c\u00f3 ng\u00e0y may m\u1eafn s\u1ebd m\u1ec9m c\u01b0\u1eddi v\u1edbi b\u1ea1n.<\/p>\n
Ch\u1eafc h\u1eb3n b\u1ea1n \u0111ang th\u1eafc t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean quay l\u00e0 bao nhi\u00eau v\u00e0 \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh nh\u01b0 th\u1ebf n\u00e0o? C\u00e2u tr\u1ea3 l\u1eddi c\u1ee7a b\u1ea1n s\u1ebd \u0111\u01b0\u1ee3c gi\u1ea3i \u0111\u00e1p ngay sau \u0111\u00e2y<\/p>\n
Nh\u00ecn ch\u00fang, theo \u0111\u00e1nh gi\u00e1 c\u1ee7a c\u00e1c chuy\u00ean gia v\u00e0 kinh nghi\u1ec7m c\u1ee7a nh\u1eefng tay ch\u01a1i chuy\u00ean nghi\u1ec7p. M\u1ed7i 1 con l\u00f4 s\u1ebd c\u00f3 t\u1ef7 l\u1ec7 tr\u00fang l\u00e0 27% v\u1edbi l\u00f4 mi\u1ec1n b\u1eafc, 18% v\u1edbi l\u00f4 mi\u1ec1n nam v\u00e0 mi\u1ec1n trung.<\/p>\n
C\u1ee5 th\u1ec3 ta c\u00f3 th\u1ec3 t\u00ednh t\u1ef7 l\u1ec7 x\u00e1c xu\u1ea5t tr\u00f9ng th\u01b0\u1edfng theo t\u1eebng lo\u1ea1i l\u00f4 xi\u00ean s\u1ebd l\u00e0 nh\u01b0 sau:<\/p>\n
+ L\u00f4 xi\u00ean 2 s\u1ebd nh\u00e2n 2 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% = 0,0729, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 7,2 %. Mi\u1ec1n nam v\u00e0 mi\u1ec1n trung: 18% x 18% = 0,0324, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 3,2%<\/p>\n
+ L\u00f4 xi\u00ean 3 ta s\u1ebd nh\u00e2n 3 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% x 27% = 0,01968, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 1,9%. Mi\u1ec1n trung v\u00e0 mi\u1ec1n nam: 18% x 18% x 18%= 0,00583, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 0,58%<\/p>\n
+ L\u00f4 xi\u00ean 4 s\u1ebd nh\u00e2n 4 l\u1ea7n: Mi\u1ec1n b\u1eafc: 27% x 27% x 27% x 27% = 0,00531, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang l\u00e0 0,5%. Mi\u1ec1n trung v\u00e0 mi\u1ec1n nam: 18% x 18% x 18% x 18% = 0,00104, t\u1ee9c x\u00e1c xu\u1ea5t tr\u00fang s\u1ebd l\u00e0 0,1<\/p>\n
<\/p>\n
Ch\u1ec9 v\u1edbi v\u00e0i v\u00ed d\u1ee5 \u0111\u01a1n gi\u1ea3n nh\u01b0 tr\u00ean, ch\u1eafc ch\u1eafn b\u1ea1n \u0111\u00e3 c\u00f3 th\u1ec3 d\u1ec5 d\u00e0ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c cho m\u00ecnh t\u1ef7 l\u1ec7 tr\u00fang l\u00f4 xi\u00ean quy cho m\u00ecnh r\u1ed3i. Ch\u00ednh v\u00ec v\u1eady, c\u00f2n ch\u1ea7n ch\u1eeb g\u00ec m\u00e0 kh\u00f4ng tham gia ch\u01a1i ngay.<\/p>\n
Sau khi \u0111\u00e3 hi\u1ec3u \u0111\u01b0\u1ee3c c\u01a1 b\u1ea3n v\u1ec1 h\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean quay n\u00e0y, ch\u00fang ta c\u00f3 th\u1ec3 \u0111\u00fac k\u1ebft l\u1ea1i c\u00e1ch ch\u01a1i l\u00f4 xi\u00ean v\u00f4 c\u00f9ng \u0111\u01a1n gi\u1ea3n nh\u01b0 sau:<\/p>\n
+ B\u01b0\u1edbc 1: Ch\u1ecdn 2 \u2013 3 \u2013 4 con l\u00f4 kh\u00f4ng tr\u00f9ng nhau theo \u0111\u00e1nh gi\u00e1 c\u1ee7a b\u1ea1n l\u00e0 c\u00f3 kh\u1ea3 n\u0103ng v\u1ec1 nh\u1ea5t.<\/p>\n
Gh\u00e9p ch\u00fang \u0111\u1ec3 t\u1ea1o ra 1 ho\u1eb7c 1 nh\u00f3m c\u00e1c c\u1ea7u xi\u00ean l\u1ea7n l\u01b0\u1ee3t l\u00e0 xi\u00ean 2, xi\u00ean 3 v\u00e0 xi\u00ean 4 (l\u01b0u \u00fd, v\u1edbi 3 ho\u1eb7c 4 con c\u00f3 th\u1ec3 t\u1ea1o ra nhi\u1ec1u xi\u00ean 2 ho\u1eb7c 3)<\/p>\n
+ B\u01b0\u1edbc 2: \u0110\u01b0a ra s\u1ed1 ti\u1ec1n (s\u1ed1 \u0111i\u1ec3m) m\u00e0 b\u1ea1n mu\u1ed1n \u0111\u00e1nh<\/p>\n
+ B\u01b0\u1edbc 3: Ch\u1edd gi\u1edd so k\u1ebft qu\u1ea3 c\u1ee7a \u0111\u00e0i b\u1ea1n ch\u01a1i<\/p>\n
+ B\u01b0\u1edbc 4: Nh\u1eadn ti\u1ec1n th\u1eafng n\u1ebfu tr\u00fang \u0111\u1ee7 c\u00e1c con l\u00f4 trong c\u1ea7u<\/p>\n
V\u00f4 c\u00f9ng \u0111\u01a1n gi\u1ea3n. T\u1ef7 l\u1ec7 tr\u00fang l\u1ea1i cao. Ng\u1ea1i g\u00ec kh\u00f4ng th\u1eed<\/p>\n
V\u1eady ch\u01a1i l\u00f4 xi\u00ean \u0103n bao nhi\u00eau? Sau \u0111\u00e2y s\u1ebd l\u00e0 s\u1ed1 ti\u1ec1n b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c n\u1ebfu tr\u00fang theo t\u1eebng lo\u1ea1i l\u00f4 xi\u00ean quay.<\/p>\n
L\u00f4 xi\u00ean 2 mi\u1ec1n b\u1eafc:<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n b\u1eafc c\u1ee7a c\u00f4ng ty x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft l\u00e0 1 \u0103n 10. T\u1ee9c l\u00e0 n\u1ebfu b\u1ea1n c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng cho c\u1eb7p xi\u00ean \u0111\u00f4i. Th\u00ec khi tr\u00fang b\u1ea1n s\u1ebd nh\u1eadn 100.000 \u0111\u1ed3ng. C\u00f2n v\u1edbi\u00a0trang c\u00e1 \u0111\u1ed9 uy t\u00edn\u00a0v\u1ec1 l\u00f4 \u0111\u1ec1 th\u00ec t\u1ef7 l\u1ec7 c\u00f2n cao h\u01a1n<\/p>\n
+ \u00a0T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n b\u1eafc theo nh\u00e0 c\u00e1i th\u00ec t\u00f9y thu\u1ed9c v\u00e0o quy \u0111\u1ecbnh c\u1ee7a t\u1eebng n\u01a1i. Th\u00f4ng th\u01b0\u1eddng t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 1 \u0103n 17, quy \u0111\u1ecbnh m\u1ee9c \u0111\u1eb7t c\u01b0\u1ee3c th\u01b0\u1eddng cao h\u01a1n so v\u1edbi \u0111\u00e1nh l\u00f4 b\u1ea1ch th\u1ee7 th\u00f4ng th\u01b0\u1eddng.<\/p>\n
L\u00f4 xi\u00ean 2 mi\u1ec1n trung v\u00e0 mi\u1ec1n nam:<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n nam hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 29.000 vn\u0111. 1 \u0111i\u1ec3m l\u00f4 tr\u00fang s\u1ebd \u0103n \u0111\u01b0\u1ee3c 650.000 \u0111\u1ed3ng, v\u00e0 c\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean mi\u1ec1n trung hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0103n \u0111\u01b0\u1ee3c 30 l\u1ea7n s\u1ed1 ti\u1ec1n b\u1ecf ra, v\u00e0 c\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n
L\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc:<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc c\u1ee7a c\u00f4ng ty x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft l\u00e0 1 \u0103n 40. V\u00ed d\u1ee5 n\u1ebfu b\u1ea1n c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng th\u00ec khi tr\u00fang, b\u1ea1n s\u1ebd nh\u1eadn v\u1ec1 400.000 \u0111\u1ed3ng.<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n b\u1eafc theo nh\u00e0 c\u00e1i th\u01b0\u1eddng c\u00f3 t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 1 \u0103n 76. M\u1ed9t s\u1ed1 nh\u00e0 c\u00e1i th\u00ec m\u1ee9c n\u00e0y c\u00f2n cao h\u01a1n n\u1eefa, nh\u1ea5t l\u00e0 v\u1edbi nh\u1eefng nh\u00e0 c\u00e1i online c\u00e1 c\u01b0\u1ee3c, con s\u1ed1 t\u1ef7 l\u1ec7 nay c\u00f3 th\u1ec3 l\u00ean t\u1edbi 5900 l\u1ea7n.<\/p>\n
L\u00f4 xi\u00ean 3 mi\u1ec1n nam v\u00e0 mi\u1ec1n trung:<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n nam hi\u1ec7n nay theo nh\u00e0 c\u00e1i th\u00ec 1 \u0111i\u1ec3m l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh l\u00e0 43.000 vn\u0111, 1 \u0111i\u1ec3m l\u00f4 tr\u00fang s\u1ebd \u0103n \u0111\u01b0\u1ee3c 3.500.000 \u0111\u1ed3ng. C\u0169ng t\u00f9y theo nh\u00e0 c\u00e1i m\u00e0 con s\u1ed1 n\u00e0y s\u1ebd thay \u0111\u1ed5i.<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n l\u00f4 xi\u00ean 3 mi\u1ec1n trung th\u00ec s\u1ebd ph\u1ee5 thu\u1ed9c v\u00e0o nh\u00e0 c\u00e1i. Tuy nhi\u00ean, th\u01b0\u1eddng th\u00ec t\u1ef7 l\u1ec7 \u0103n s\u1ebd cao h\u01a1n so v\u1edbi xi\u00ean 3.<\/p>\n
L\u00f4 xi\u00ean 4 mi\u1ec1n b\u1eafc:<\/p>\n
+ T\u1ef7 l\u1ec7 \u0103n c\u1ee7a l\u00f4 xi\u00ean quay 4 l\u00e0 1\/100. T\u1ee9c l\u00e0 khi c\u01b0\u1ee3c 10.000 \u0111\u1ed3ng, n\u1ebfu tr\u00fang b\u1ea1n s\u1ebd \u0103n 1.000.000 \u0111\u1ed3ng.<\/p>\n
+ T\u1ea1i c\u00e1c nh\u00e0 c\u00e1i th\u00ec s\u1ed1 ti\u1ec1n \u0103n c\u00f3 th\u1ec3 g\u1ea5p l\u00ean r\u1ea5t nhi\u1ec1u. Th\u1eadm ch\u00ed g\u1ea5p 320 l\u1ea7n s\u1ed1 ti\u1ec1n ban \u0111\u1ea7u b\u1ea1n b\u1ecf ra. T\u1ee9c l\u00e0 1 \u0103n 320.<\/p>\n
L\u00f4 xi\u00ean 4 mi\u1ec1n trung v\u00e0 mi\u1ec1n nam: H\u00ecnh th\u1ee9c ch\u01a1i l\u00f4 xi\u00ean n\u00e0y theo c\u00e1c nh\u00e0 c\u00e1i hi\u1ec7n nay th\u01b0\u1eddng c\u00f3 t\u1ef7 l\u1ec7 \u0103n r\u1ea5t cao. C\u00f3 th\u1ec3 l\u00ean t\u1edbi 1 \u0103n 720<\/p>\n